CHEMG2PT

CHENMKO ENTERPRISE CO.,LTD SURFACE MOUNT Dual Digital Silicon Transistor VOLTAGE 50 Volts APPLICATION * Switching circuit, Inverter, Interface circuit, Driver circuit. C HEMG2PT CURRENT 30 mAmpere FEATURE * Small surface mounting type. (SOT-553) * High current gain. * Suitable for high packing density. * * * * Low colloector-emitter saturation. High saturation current capability. Two CHDTC144E transistors in one package. Built in bias resistor(R1=47kΩ, Typ. ) (4) (3) SOT553 0.50 0.9~1.1 (5) (1) 0.50 1.5~1.7 0.15~0.3 MARKING * G2 0.5~0.6 1.1~1.3 0.19~0.18 1.5~1.7 CIRCUIT 3 R1 R2 2 R1 R2 1 4 5 Dimensions in millimeters SOT553 LIMITING VALUES In accordance with the Absolute Maximum Rating System (IEC 60134). SYMBOL VCC VIN IO DC Output current IC(Max.) PTOT TSTG TJ RθJ-A Note 1. Transistor mounted on an FR4 printed-circuit board. Total power dissipation Storage temperature Junction temperature Thermal resistance junction - ambient air Tamb ≤ 25 OC, Note 1 PARAMETER Supply voltage Input voltage CONDITIONS − -10 − − − −55 − − MIN. MAX. 50 +40 30 mA 100 200 +150 150 625 mW O UNIT V V C C C/W 2004-07 O O RATING CHARACTERISTIC ( CHEMG2PT ) CHARACTERISTICS Tamb = 25 °C unless otherwise speciÞed. SYMBOL VIoff) VI(on) VO(on) II IC(off) hFE R1 R2/R1 fT PARAMETER Input off voltage Input on voltage Output voltage Input current Output current DC current gain Input resistor Resistor ratio Transition frequency IE=-5mA, VCE=10.0V f=100MHz = CONDITIONS IO=100uA; VCC=5.0V IO=2mA; VO=0.3V IO=10mA; II=0.5mA VI=5V VI=0V; VCC=50V IO=5mA; VO=5.0V − − − − 68 32.9 0.8 − MIN. 0.5 − − − − − − 47 1.0 250 TYP. MAX. − 3.0 0.3 0.18 0.5 − 61.1 1.2 − KΩ MHz V V mA uA UNIT Note 1.Pulse test: tp≤300uS; δ≤0.02. RATING CHARACTERISTIC CURVES ( CHEMG2PT ) Typical Electrical Characteristics Fig.1 Input voltage vs. output current (ON characteristics) 100 50 VO=0.3V Fig.2 Output current vs. input voltage (OFF characteristics) 10m 5m OUTPUT CURRENT : Io (A) VCC=5V INPUT VOLTAGE : VI(on) (V) 20 10 5 2 1 500m 200m 100m 100 200 500 1m 2m 5m 10m 20m 50m 100m Ta =- 40OC 25OC = 100OC 2m 1m 500 200 100 50 20 10 5 2 1 0 Ta=100OC 25OC -40 OC 0.5 1.0 1.5 2.0 2.5 3.0 OUTPUT CURRENT : IO (A) INPUT VOLTAGE : VI(off) (V) Fig.3 DC current gain vs. output current 1k 500 DC CURRENT GAIN : GI Fig.4 Output voltage vs. output current 1 500m OUTPUT VOLTAGE : VO(on) (V) VO =5V Ta=100OC 25OC -40OC lO/lI=20 Ta=100OC 25OC -40 OC 200 100 50 20 10 5 2 200m 100m 50m 20m 10m 5m 2m 1 100 200 500 1m 2m 5m 10m 20m 50m100m 1m 100 200 500 1m 2m 5m 10m 20m 50m 100m OUTPUT CURRENT : IO (A) OUTPUT CURRENT : IO (A)