CHEMH10PT

CHENMKO ENTERPRISE CO.,LTD SURFACE MOUNT Dual Digital Silicon Transistor VOLTAGE 50 Volts APPLICATION * Switching circuit, Inverter, Interface circuit, Driver circuit. C HEMH10PT CURRENT 100 mAmpere FEATURE * Small surface mounting type. (SOT-563) * High current gain. * Suitable for high packing density. * Low colloector-emitter saturation. * High saturation current capability. * Internal isolated two NPN transistors in one package. * Two CHDTC23J chips in one package. * Built in bias resistor(R1=2.2kΩ, Typ. ) SOT-563 (1) (5) 0.9~1.1 0.15~0.3 (3) (4) 0.50 0.50 1.5~1.7 MARKING * H0 1.1~1.3 0.5~0.6 0.09~0.18 6 R1 R2 4 CIRCUIT 1.5~1.7 R2 1 R1 3 Dimensions in millimeters SOT-563 LIMITING VALUES In accordance with the Absolute Maximum Rating System (IEC 60134). SYMBOL VCC VIN IO DC Output current IC(Max.) PTOT TSTG TJ RθJ-A Note 1. Transistor mounted on an FR4 printed-circuit board. 2004-07 PARAMETER Supply voltage Input voltage CONDITIONS − -5 − − Tamb ≤ 25 OC, Note 1 − MIN. MAX. 50 +12 100 V V UNIT mA 100 200 +150 150 833 mW O Total power dissipation Storage temperature Junction temperature Thermal resistance −55 − junction - ambient air − C C C/W O O RATING CHARACTERISTIC ( CHEMH10PT ) CHARACTERISTICS Tamb = 25 °C unless otherwise speciÞed. SYMBOL VIoff) VI(on) VO(on) II IC(off) hFE R1 R2/R1 fT PARAMETER Input off voltage Input on voltage Output voltage Input current Output current DC current gain Input resistor Resistor ratio Transition frequency IE=5mA, VCE=10.0V f=100MHz = CONDITIONS IO=100uA; VCC=5.0V IO=5mA; VO=0.3V IO=5mA; II=0.25mA VI=5V VI=0V; VCC=50V IO=10mA; VO=5.0V − − − 80 1.54 16.8 − MIN. 0.5 − − 0.1 − − − 2.2 21 250 TYP. − 1.1 0.3 3.6 0.5 − 2.86 25.2 − KΩ MHz MAX. V V V mA uA UNIT Note 1.Pulse test: tp≤300uS; δ≤0.02. RATING CHARACTERISTIC CURVES ( CHEMH10PT ) Typical Electrical Characteristics Fig.1 Input voltage vs. output current (ON characteristics) 10 VO=0.2V Fig.2 Output current vs. input voltage (OFF characteristics) 100m VCC=5V OUTPUT CURRENT : Io (A) INPUT VOLTAGE : VI(on) (V) 10m Ta= 75O C 25OC -25 OC Ta =- 25OC 25OC = 75OC 1.0 1m 100u 10u 0.1 0 10m 20m 30m 40m 50m 1u 0 1 2 3 4 5 6 7 8 9 10 OUTPUT CURRENT : IO (A) INPUT VOLTAGE : VI(off) (V) Fig.3 DC current gain vs. output current 1k VO =10V Ta= 75OC 25OC -25OC OUTPUT VOLTAGE : VO(on) (V) Fig.4 Output voltage vs. output current 1 lO/lI=10 Ta= 75 OC 25OC -25 OC DC CURRENT GAIN : GI 100m 100 10m 10 1m 10m OUTPUT CURRENT : IO (A) 100m 1m 0 10m 20m 30m 40m 50m OUTPUT CURRENT : IO (A)